x^2-2.1x+1.04=0

Solution for x^2-2.1x+1.04=0 equation:

x^2-2.1x+1.04=0

a = 1; b = -2.1; c = +1.04;
Δ = b2-4ac
Δ = -2.12-4·1·1.04
Δ = 0.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.1)-\sqrt{0.25}}{2*1}=\frac{2.1-\sqrt{0.25}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.1)+\sqrt{0.25}}{2*1}=\frac{2.1+\sqrt{0.25}}{2}
$